Question

Inverse of functions: g(x) =1/x + 2/3

Answer 1

\[\Large g(x) = \frac1x + \frac23\]
yes?

Answer 2

yup

Answer 3

bilis mag type puteek

Answer 4

Well, usuals...
You might want to skip to the essentials... replace g(x) with x
and replace x with y.
\[\Large x = \frac1y + \frac23\]

Answer 5

Now... can you solve for y?

Answer 6

find the lcd

Answer 7

Sure... that might work, but it'll take a long time... why don't you transpose the 2/3 to the other side first?

Remember, put all terms with y on one side, and all terms without, on the other.

Answer 8

x-2/3=1/y

Answer 9

That's good :)
\[\Large x - \frac23 = \frac1y\]

NOW you use lcd in the LEFT SIDE.

Answer 10

baket 2/3 nilipat?? xDDD

Answer 11

Kasi wala siyang y.

Answer 12

I said... bring all terms without y to the other side.

Answer 13

ai ou, xD ahahah na iimagine ko na y ung x. xD

Answer 14

baka naman kailangan mo na magpahinga? XD

Answer 15

hahahaha, xD sheet, may play pa kami sa eng taeee, cge continue na lang, xD

Answer 16

oo nga continue...
\[\Large x - \frac23= \color{red}?\]
Find the LCD nga eh...

Answer 17

hahah, xD 3x???

Answer 18

...
\[\large x = \frac{3x}{3}\]
sige... tapos...?

Answer 19

diba dapat 3-2x/3x =2/3????

Answer 20

teka natatanga ako...
\[\Large x + \frac23 = \frac{3x}3 +\frac23 = \color{red}?\]

Answer 21

mali pa yung symbol... - yun hindi dapat +

Answer 22

san nanggaling 3x/3???

Answer 23

feeling ko kailangan ko nang matulog,,

Answer 24

idk sorry

Answer 25

para pareho yung denominator doon sa 2/3
tandaan...:
\[\Large \frac{a}c+ \frac{b}c = \frac{a+b}c\]
para isa na lang yung fraction bar

Answer 26

geh, geh,, pre matutulog na lang, ako mukhang need koh nah, xD waaaa salamaat ulit,, xDDD