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Mathematics 21 Online
OpenStudy (anonymous):

If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).

terenzreignz (terenzreignz):

True or false?

OpenStudy (anonymous):

Yuppp. :)

terenzreignz (terenzreignz):

well then, for all circles in the form: \[\Large (x - \color{red}h)^2 + (y - \color{blue}k)^2 = \color{green}r^2\] The center is ALWAYS at \(\large (\color{red}h \ , \color{blue}k)\) From that, deduce what you will :)

OpenStudy (anonymous):

So it's true,right?

terenzreignz (terenzreignz):

Is it? ;)

terenzreignz (terenzreignz):

LOL yeah, it is :)

OpenStudy (anonymous):

Hhah, scared me for a minute. Thank you!

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