b

Question

b

amistre64 · Answer

cooling towers tend to be skinny along the x direction, not the y direction

amistre64 · Answer

in other words, you should have an x^2-y^2 setup,  not y^2-x^2

amistre64 · Answer

id suggest that if you want the walls to be more upright, that you make the slope b/a greater

if you want them to be more bendy, make the slope b/a smaller

the slope refers to the asymptotes of the hyperbola

the vertices of the hyperbola will be defined by +-k  depending on how wide you want the hyperbola to be

amistre64 · Answer

$$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$$
spose you want the vertices to be 350 feet apart, then a=350/2 = 175
$$\frac{x^2}{(175)^2}-\frac{y^2}{b^2}=1$$
spose you want a relatively shallow bend, say a slope of 4

then:  b/175 = 4

b = 4(175) = 600
$$\frac{x^2}{(175)^2}-\frac{y^2}{(600)^2}=1$$

amistre64 · Answer

http://www.wolframalpha.com/input/?i=x%5E2%2F175%5E2-y%5E2%2F600%5E2%3D1

amistre64 · Answer

editing the content out of your question is not a good thing to do ... it suggests that you are trying to hide the fact that you received help from here.

amistre64 · Answer

if this conduct continues, we will have no choice but to suspend your account.