Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown. I'll provide a picture, please help me.
First find the slope for the line given ??
line through the points 0 comma 3 and 3 comma 5 with the point 2 comma negative 3 not on the line?? Idk how to do this ;(
ok the line that is given to you have a slope of 2/3 rise and run, can you see that ??
honestly I can't see that I have no clue how to do this. I'm homeschooled and get a bit stumped, since I don't have a teacher to walk me through..
you need to find the equation that is perpendicular to that line, to be perpendicular it needs to be opposite reciprocal Do you know what is opposite reciprocal of 2/3 ??
the way I know the slope is 2/3, if you see the point (0,-3) every time you count up 2 and 3 to the side you will find a point
So the answer will be the last choice?
no, we are only half way to get the answer so do you know what is opposite reciprocal ??
yes or no
no. Well when u flip the equation right?
right opposite reciprocal you need to change sign as well so the opposite reciprocal of 2/3 = -3/2
so the answer is the first one? y=-3/2x
no the problem is giving you a point (2,-3), and the question is what is the equation that passes through those points, so you use formula y=mx+b, to find b
so you have -3 = -3/2(2) + b b = 0, so the equation would be y = -3/2x + 0 which is the same as y = -3/2x
so what would the answer be O_O
that is the answer y = -3/2x
oh ok thanks
yw :)
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