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Mathematics 20 Online
OpenStudy (anonymous):

Express the circumference of a circle, C, as a function of its area, A.

OpenStudy (whpalmer4):

\[C = 2 \pi r\]\[A = \pi r^2\]Solve latter equation for \(r\) in terms of \(A\) and substitute into the first equation. \[\frac{A}{\pi} = r^2\]\[r = \sqrt{\frac{A}{\pi}}\] you do the substitution and I'll check it

OpenStudy (anonymous):

\[C=2\pi \sqrt{\frac{ A }{ \pi }}\]

OpenStudy (jhannybean):

Good job.

OpenStudy (jhannybean):

You can further reduce that as follows. \[\large C = 2 \times \ \cancel{\sqrt{\pi}} \times \sqrt{\pi} \times \frac{\sqrt{A}}{ \cancel{\sqrt{\pi}}} = 2\sqrt{A \pi}\]

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