Question

find the inverse of the function:
g(x)=2x^2+6x+2

Answer 1

hahahaha

Answer 2

hirap naman nito

Answer 3

waah, grabeh, xDD andali lang nian ehh

Answer 4

ganun ba?
pa demo nga, master...

Answer 5

awtzs, nakakahiya namans a college diyan diba?? xDDDD

Answer 6

magaling ka naman eh :P
lalabas muna ako... pagbalik ko dapat nai-post mo na yung sagot mo... Derek-sensei :D

Answer 7

waah, xDD not japanese. xDDD

Answer 8

Sifu-Derek

Answer 9

i am so lost :P

Answer 10

terenz: this is so hard
derek: waaah 'grabeh' (grave?) this is easy (eh)
terenz: is that so? demonstrate, master
derek: awtzs, wouldn't want to put the college student to shame, no?
terenz: you're so good after all? I'll go out for a while, when I go back, you better post your
answer, derek-sensei


That's the gist of it @hartnn :)

Answer 11

lol, thank you!

Answer 12

filipino -english translator , ahahah, xD

Answer 13

back to solving this ?

Answer 14

i guess completing the square will help....

Answer 15

@mathslover

Answer 16

completing the square.... you know how to do it?

Answer 17

yup, (b/2)^2

Answer 18

It would have been more polite to respond to @hartnn :D
anyway, first divide both sides of
\[\Large y = 2x^2 + 6x +2 \]
by 2 what do you get?

Answer 19

xD

Answer 20

y/2=2x^2+6x+2/2

Answer 21

yeah... so? simplify
remember
\[\large 2x^2 + 6x + 2 = 2(x^2 + 3x + 1)\]

Answer 22

yup,, xD

Answer 23

Well? Simplify.
\[\Large \frac{y}2 = \color{red}?\]

Answer 24

y/2

Answer 25

y/2=x^2+3x+1

Answer 26

@terenzreignz ,, busy????

Answer 27

Overreacting much? :P
You're the one that took long to answer my question :P
Anyway, you're right.
Now complete the square on the right side... using whatever technique was taught to you.

Answer 28

huh?? panu ma complete ung square if may c na sia

Answer 29

<sarcastic tone>
oo nga no? ilipat mo kaya yung 'c' sa kabila? >:)
<end sarcastic tone>

Answer 30

hahaah, xDDDD

Answer 31

.. fine... -.-
\[\Large \frac{y}2 - 1 = x^2+3\]

o... masaya ka na? :D

Answer 32

nagets ko naman ehh. -____-

Answer 33

syempre hinde, may typo ako eh :D
\[\Large \frac{y}2 - 1 = x^2+3\color{red}x\]

Answer 34

y/2-1+x^2+3+9/4

Answer 35

+?
o =?
y/2 -1 = ...blabla

Answer 36

\[\Large \frac{y}2 - 1 \color{red}{+\frac94}= x^2 + 3\color{green}x \color{red}{+\frac94}\]
Wag kalimuta na kailangan sa PAREHONG side i-add yung 9/4... para patas naman, diba? :P

Answer 37

*kalimutan

Answer 38

aiyt, ahahah, xD nag crash ung broswer, ou nga noh,??? xD ahahah di ko napansin

Answer 39

o... pano simplify mo yung left-side, tapos i-express mo yung right-side bilang perfect square.

Answer 40

wait lang, xDD diba kailangan ntin i change ung x and y???

Answer 41

ung sa pinaka start??

Answer 42

di i-change mo.
kung saan ka masaya suportahan taka
\[\Large \frac{x}2 - 1 \color{red}{+\frac94}= y^2 + 3\color{green}y \color{red}{+\frac94}\]

Answer 43

ahahahah, xDDDD

Answer 44

You must understand, switching x and y is just a formality. In fact, it wouldn't make a difference in essence if we keep them as is, and do the changing afterwards.

Answer 45

okay ,,,

Answer 46

so... simplify the left, express the right as a perfect square... let's go now...
vamos!

Answer 47

2x+5/4

Answer 48

galing naman ni kuya :D
yung kanan naman :P

Answer 49

hala. xDDD

Answer 50

di ako marunong sa right side. xDDDD

Answer 51

(y+3/2)(y+3/2)??

Answer 52

O, kaya mo naman pala eh ... -.-

\[\Large x^2 +bx + \frac{b^2}4 = \left(x+\frac{b}2\right)^2\]

Answer 53

\[\Large \frac{2x+5}{4}= \left(y+\frac32\right)\left(y+\frac32\right)=\left(y+\frac32\right)^2\]

Answer 54

tapos???

Answer 55

tápos? tapós!
\[\Large \frac{2x+5}{4}= \left(y+\frac32\right)^2\]
Don't be shy, get the square root of both sides...