Question

Find the area of the triangle with B= 67°, a=11 yd, and c = 24 yd.

Answer 1

right angle triangle...?

Answer 2

thts not what it shows, as far as i know lol

Answer 3

then law of cosines...?
c^2 = a^2 + b^2 -2ab cos y

Answer 4

in this case
a = 11
b = 24
y = 67 degrees

Answer 5

k if you've never been taught rule of cosines, then you shouldnt be expected to know it

Answer 6

so lets assume its a right angled triangle
use the lenght of AC as the verticle height
and the length of CB as the base

Answer 7

so Area of triangle = 1/2 x base x vertical height

Answer 8

use pythag theorum to work out length AC
\[h^2 = a^2 + b^2 \]

Answer 9

u ok with all of that ash?

Answer 10

um..yes?

Answer 11

cool, cya then

Answer 12

O.O ok

Answer 13

ok... well, what did u get for the length AC?

Answer 14

h^2 = a^2 + b^2
24^2 = 11^2 + AC^2
...
so
576 = 121 + AC^2
AC^2 = 455
so
AC = sqrt 455
= approx 21.3 ish

Answer 15

u doin ok there ash?
need me to elaborate on anything so far?

Answer 16

i jus need to find the area lool

Answer 17

so Area of triangle = 1/2 x base x vertical height
= 0.5 x 11 x 21.3
= ...?

Answer 18

=...? @ashleighgirl

Answer 19

117.15

Answer 20

spot on!

Answer 21

slaters ;D

Answer 22

^~^

Answer 23

none of those were my answers..
a) 121.5 yd²

b) 243 yd²

c) 51.8 yd²d

d) 103.2 yd²

Answer 24

area = ab sinC/2 then

Answer 25

= 121.51 yd^2

Answer 26

note to self, it wasnt a right angled triangle then ;(

Answer 27

awe...
</3

Answer 28

awwww, im sorry

Answer 29

tiz okay

Answer 30

k then love u bye!

Answer 31

^~^