Question

What is the value of the y variable in the solution to the following system of equations?

3x − 6y = 3
7x − 5y = −11

−2

−3

x can be any number as there are infinitely many solutions to the system.

There is no x value as there is no solution to the system

Answer 1

Multiply the first equation by 7
Multiply the second equation by 3
Then subtract the new second equation from the new first equation.
Then solve for y.

Answer 2

wait i got x-27=54
+27 81
x=

Answer 3

No.
Here's the first equation:
3x - 6y = 3
Can you multiply the entire equation by 7? That means multiply every term by 7.

Answer 4

ya 21x-42=21

Answer 5

then what

Answer 6

I wrote all the instructions above. Just follow them.

Answer 7

Look at my first response.

Answer 8

ok

Answer 9

Don't forget the y with the 42:
21x-42y=21

Answer 10

thats what i got for the first one but i got this for yhe second one:21x-15=-33

Answer 11

No it's not. You left the y out of the first one, and now you left the y out of the second one.

Answer 12

you want to cancel out either a y value or an x value...

Answer 13

It should read:
21x - 15y = -33

Answer 14

ya igot that one

Answer 15

First you just multiply the entrie equations by the numbers. Leaving out the variable y does not mean you canceled it. It means you have an error. You can't just leave y out.

Answer 16

ok

Answer 17

here are the two correct equations after multiplying:
21x - 42y = 21
21x - 15y = -33
Now subtract the second equation from the first one.
21x - 21x - 42y - (-15y) = 21 - (-33)

Answer 18

ok see it

Answer 19

i got x-27=21-(-33)

Answer 20

What is 21x - 21x?

Answer 21

21x - 21x - 42y - (-15y) = 21 - (-33)
0 -27y = 54

Answer 22

Now divide both sides by -27 to get y

Answer 23

ya

Answer 24

thankyou

Answer 25

wlcm