Question

help me please! (1/6x2 ) = ( 1/3x2) - (1/x)

Answer 1

\[\frac{ 1 }{ 6*2 }=\frac{1 }{ 3*2 }-\frac{ 1 }{ x }\]

Answer 2

u need find a common denominator...

Answer 3

\[\frac{ 1 }{ 12 }=\frac{ 1 }{ 6 }-\frac{ 1 }{ x}\]

Answer 4

common denominator 12x so....
\[\frac{ 1(x) }{ 12(x) }=\frac{ 1(2x) }{ 6(2x) }-\frac{ 1(12) }{ x(12)}\]

Answer 5

whatever you do to the bottom, u also have to do to the top^^^

Answer 6

so u get...
\[\frac{ 1x }{ 12x }=\frac{ 2x }{ 12x }-\frac{ 12 }{ 12x}\]
u can get rid of the 12x on the bottom since it wont make a difference since its under all of the terms ... now we get
1x = 2x-12

Answer 7

subtract 2x on both sides
1x =2x-12
-2x -2x u get: -1x=-12

Divide 1x on both sides, since its the term with the variable, and u want to get the variable alone.... so

-1x=-12
/-1 /-1 final answer x=12

Answer 8

FINAL ANSWER x=12,,, srry for taking up alot of space, lol