the distance travelled by a body falling freely from in the 1st, 2nd and 3rd seconds, are in the ratio
a)1:2:3 b)1:3:5 c)1:4:9 d)3:2:1

Question

the distance travelled by a body falling freely from in the 1st, 2nd and 3rd seconds, are in the ratio 
a)1:2:3   b)1:3:5  c)1:4:9      d)3:2:1

shamim · Answer

i think this is a problem of physics

shamim · Answer

anyway let the initial velocity$$u=0$$

shamim · Answer

the free falling body travel the distance in first 1 second is$$h _{1}=ut+\frac{ 1 }{ 2 }g t ^{2}=0 \times 1+\frac{ 1 }{ 2 }g \times 1^{2}=\frac{ 1 }{ 2 }g$$

shamim · Answer

did u get it

shamim · Answer

i got the result $$1:3:5$$

shamim · Answer

i wanna show procedure if u want

anonymous · Answer

since the average of things falling is 9.8m/s2, then according to your question, the answer would be:
9.8 : 39.2 : 88.2
so. the answer would be: c) 1:4:9