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What would be the point-slope equation, using these two points: (-5, 3) and (4, -6)?
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Given that AC and AE are common external tangents of circle G and circle D, FE = 15, GF = 3, and AG = 5, which is the length of AC?
slope formula is \[\frac{ y2-y1 }{ x2-x1 }\]
so once you plug in ur numbers \[\frac{ -6-3 }{ 4-(-5) }\]
After that we put the slope in the formula, \[y-y0= m(x-x0)\] ?
do you mean onece you find the slop you have to put it into slope interscept form?
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Once I find the slope, I have to make a point-slope equation. I think that's the formula ^^
the formula you have is point slope form that is right LOL sorry I got confused
It's cool, I got it. Thanks! (:
No Problem :)
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