Determine whether ΔABC ~ ΔFDE. If they are similar, what postulate or theorem proves their similarity?
Angle-Angle Similarity Postulate
Similarity cannot be determined.
Side-Angle-Side Similarity Postulate
Side-Side-Side Similarity Postulate
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OpenStudy (anonymous):
OpenStudy (anonymous):
@ganeshie8 what do you think?
ganeshie8 (ganeshie8):
tell me first wat do u think :)
OpenStudy (anonymous):
i would say it was side angle side but the sides given are not the same
ganeshie8 (ganeshie8):
both have same angle 112. but the first triangle is SSA
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ganeshie8 (ganeshie8):
where as second triangle is SAS
ganeshie8 (ganeshie8):
order itself is not matching between both the triangles. SO you cannot determine the similarity !
ganeshie8 (ganeshie8):
does that make some sense
OpenStudy (anonymous):
ya i got it thankyou
can you help me with more q?
ganeshie8 (ganeshie8):
sure :) u seem to be trying to learn things.... so why not :D
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OpenStudy (anonymous):
In the figure, ΔABC ~ ΔDEF. Solve for x.
x = 16.36
x = 55
x = 2.2
x = 66
OpenStudy (anonymous):
this one i have no idea
ganeshie8 (ganeshie8):
when triangles are similar, ratio of sides is equal
ganeshie8 (ganeshie8):
look at the first lil triangle
ganeshie8 (ganeshie8):
ratio of sides = \(\large \frac{11}{6}\)
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ganeshie8 (ganeshie8):
In the second triangle,
ratio of sides = \(\large \frac{x}{30}\)
ganeshie8 (ganeshie8):
since triangles are similar, both ratios equal eachother
OpenStudy (anonymous):
would be 55
ganeshie8 (ganeshie8):
\(\large \frac{11}{6} = \large \frac{x}{30}\)
ganeshie8 (ganeshie8):
yes x = 55! good work !
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OpenStudy (anonymous):
AB II DE. Solve for x.
x = 19
x = 12
x = 9
x = 16
OpenStudy (anonymous):
ganeshie8 (ganeshie8):
setup a proportion. the ratio of segments of sides equal each other
ganeshie8 (ganeshie8):
\(\large \frac{x-3}{12} =\frac{4}{3}\)
ganeshie8 (ganeshie8):
solve x
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ganeshie8 (ganeshie8):
can u ? :)
OpenStudy (anonymous):
ummm i did something wrong lol because what i got is not one of the options lol
ganeshie8 (ganeshie8):
\(\large \frac{x-3}{12} =\frac{4}{3}\)
ganeshie8 (ganeshie8):
cross multiply
ganeshie8 (ganeshie8):
\(3(x-3) = 4(12)\)
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