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Mathematics 20 Online
OpenStudy (anonymous):

Determine whether ΔABC ~ ΔFDE. If they are similar, what postulate or theorem proves their similarity? Angle-Angle Similarity Postulate Similarity cannot be determined. Side-Angle-Side Similarity Postulate Side-Side-Side Similarity Postulate

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8 what do you think?

ganeshie8 (ganeshie8):

tell me first wat do u think :)

OpenStudy (anonymous):

i would say it was side angle side but the sides given are not the same

ganeshie8 (ganeshie8):

both have same angle 112. but the first triangle is SSA

ganeshie8 (ganeshie8):

where as second triangle is SAS

ganeshie8 (ganeshie8):

order itself is not matching between both the triangles. SO you cannot determine the similarity !

ganeshie8 (ganeshie8):

does that make some sense

OpenStudy (anonymous):

ya i got it thankyou can you help me with more q?

ganeshie8 (ganeshie8):

sure :) u seem to be trying to learn things.... so why not :D

OpenStudy (anonymous):

In the figure, ΔABC ~ ΔDEF. Solve for x. x = 16.36 x = 55 x = 2.2 x = 66

OpenStudy (anonymous):

this one i have no idea

ganeshie8 (ganeshie8):

when triangles are similar, ratio of sides is equal

ganeshie8 (ganeshie8):

look at the first lil triangle

ganeshie8 (ganeshie8):

ratio of sides = \(\large \frac{11}{6}\)

ganeshie8 (ganeshie8):

In the second triangle, ratio of sides = \(\large \frac{x}{30}\)

ganeshie8 (ganeshie8):

since triangles are similar, both ratios equal eachother

OpenStudy (anonymous):

would be 55

ganeshie8 (ganeshie8):

\(\large \frac{11}{6} = \large \frac{x}{30}\)

ganeshie8 (ganeshie8):

yes x = 55! good work !

OpenStudy (anonymous):

AB II DE. Solve for x. x = 19 x = 12 x = 9 x = 16

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

setup a proportion. the ratio of segments of sides equal each other

ganeshie8 (ganeshie8):

\(\large \frac{x-3}{12} =\frac{4}{3}\)

ganeshie8 (ganeshie8):

solve x

ganeshie8 (ganeshie8):

can u ? :)

OpenStudy (anonymous):

ummm i did something wrong lol because what i got is not one of the options lol

ganeshie8 (ganeshie8):

\(\large \frac{x-3}{12} =\frac{4}{3}\)

ganeshie8 (ganeshie8):

cross multiply

ganeshie8 (ganeshie8):

\(3(x-3) = 4(12)\)

ganeshie8 (ganeshie8):

\(x-3 = 4(4)\)

ganeshie8 (ganeshie8):

\(x-3 = 16\)

ganeshie8 (ganeshie8):

\(x = 19\)

OpenStudy (anonymous):

oh ok thankyou

ganeshie8 (ganeshie8):

np :)

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