Question

Write the equation of the line that is parallel to the line 4x − 3y = −12 and passes through the point (−3, 4).

y = x + 8

y = x + 3

y = −x + 8

y = −x + 3

Answer 1

they all have 4/3

Answer 2

can u explain

Answer 3

if two lines are parallel then they have the same slope.

find the slope, and then use the order pair they gave you to write your new equation in standard form

Answer 4

.-. eeeeek i dont know how to explain it lol and oh okay thanks robz8

Answer 5

thanxs robz..

Answer 6

Solve 4x − 3y = −12 for y.
What do you get?

Answer 7

-4?

Answer 8

4x − 3y = −12
-4x -4x
---------------
-3y = -4x - 12
Divide both sides by -3:
y = (4/3)y + 4
Slope is 4/3, ok?

Answer 9

ok

Answer 10

A parallel line to it must also have slope = 4/3. No choice given has a slope of 4/3. Are these the choices from another problem?

Answer 11

for parallel lines, they have the SAME slope, but different y-intercepts (the value of 'b' is different).

4x-3y= -12

-3y= -12 -4x

y= 4 +4/3x

In other words, your new equation is y= 4/3x +b

So using y= 4/3x +b and the point (-3,4):

4= 4/3(-3/1) +B

4= -12/3 +b

4= -4 +b

b= 8

Therefore y= 4/3x +8

Answer 12

no i think nurali helped me thanks

Answer 13

Parallel lines have same slopes therefore writing the given eq as below
4x − 3y = −12
i.e. 3y = 4x+12
i.e. y = 4/3 x+ 4
comparing it with y = mx + c, we get
Slope of the required line m = 4/3
since req line passes through (−3, 4) i.e. x1=-3, y1= 4
Now the eq of line in slope point for is given as
y-y1=m(x-x1)
i.e. y-4=4/3(x+3)
i.e. y=4/3x+8 and this is the required eq of line