Question

What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-intercept form?

y = 3x + 4

y = 1/3x + 3

y = –3x – 6

y =1/3 x – 5

Answer 1

y = -3x + 1 ---> the slope for this line is -3

Because the slope is -3, the slope of the perpendicular line would be the inverse reciprocal, which is 1/3

You want the line to pass through (-6, 1). The equation for the line is y = 1/3x + b

Find b. Plug in -6 for x and 1 for y.

1 = 1/3(-6) + b
1 = -2 + b
b = 3

So the equation for the perpendicular line is y = 1/3x + 3 B

Answer 2

-3*1/3 should always equal -1 to find the slope to a perpendicular slope

Answer 3

so the answer is in fact -3