[6.03] What is the value of the y variable in the solution to the following system of equations? 3x + 2y = 6 2x + 3y = −6 6 −3 3 −6
just multiply ur 1st equation by 2 and multiply ur 2nd equation by 3 then subtract those 2 equations
what
Why don't you do the Guess, Check, and Revise method? What you just do is just plug in the integers towards the variables of x and y.
u hv 2 equations r \[3x+2y=6....................(1)\]
\[2x+3y=-6.........................(2)\]
I think that the answer to the variable is (-6).
if u multiply ur equation (1) by 2 u will get\[6x+4y=12...................(3)\]
so the answer 3??
anyway do the math first
Oh never mind my answer.
then u hv to multiply ur equation (2) by 3, then u will get\[6x+9y=-18......................(4)\]
I suck at math.
now subtract (4) frm equation (3)
Don't think it like that. Math seems difficult at first, but when you have the confidence, you can understand the math.
1?
y=-6
Yes that's what I had just said. I figured that out by filling in the -6 in the x value and also the y value.
Anyhow, if there was two answers to the x function then it wouldn't be made into a function. This equation would have been a quadratic equation, when you have two answers.
oh sorry i been working on math all night i feel so dum :(
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