Question

Find all solutions of the equation in the interval [0,2π)

sinθ +1 = 0

Is the answer just π?

Answer 1

sin theta = -1
the angle whose sine is 1 in the first quadrant is pi/2
hope this helps

Answer 2

sin theta is -1 so wouldn't you be looking for the angle whose sine is -1? That's where I got π from.

Answer 3

0,

remember, the sine is the y component, so at theta = pi, sine theta = 0

Answer 4

@cwrw238 was probably hoping you would remember that -sin(u) = sin(-u) = sin(2pi-u)

Answer 5

If that's where you're pointing to, would the answer be 3π/2 then? It's asking specifically for radians in terms of π.

Answer 6

sin (3pi/2) = -1, yes.