Question

pink

Answer 1

if you set the equation to 0 so \[2x^2 -8x -10 = 0\] you will find your x intercepts

Answer 2

then set x = 0 then you will have \[2(0)^2 - 8(0) - 10 = y\] then you will have your y-intercept

Answer 3

Hmm... to factor out \( 2x^2-8x-10\) This is how we can approach the factorization. As @hobbs978 stated, we have to set it to 0, got that. Then...factor out a 2. \[\large 2(x^2-4x-5)\]Simplify stuff inside parenthesis. What two numbers give you -4 when adding and -5 when multiplying?\[\large 2(x-5)(x+1)\]Equal these two to 0. \[\large 2(x-5)=0\]\[\large x+1=0\]Solve for the x's

Answer 4

And you can verify it with your graph. http://fooplot.com/plot/dqpsc5h301

Answer 5

Thanks for clearing up my question and making a better question :)