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Add these two complex numbers : (2 + 3i) + (-3 - i)
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complex numbers act as variables so what this is \[(2 + 3i) + (-3-i)=(2-3)(3i-i)= -1+2i\]
You wrote that middle part incorrectly: \[(2+3i) + (-3-i) = (2-3) + (3-1)i = -1 + 2i\]
true thanks for catching that i've been having a bad day :(
that means it can only get better, right? :-)
until i hit \[- \infty\]i can only go up
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go down* see its getting worst lol
lol :0 imma stop talking lol
lol i saw that no reason to delete is XD
anyhow, I just didn't want the OP to get confused and think there was a multiplication going on in the middle step there...
yea no problem thanks for the fix
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