Question

csc^2 θ = 8 cot θ + 10 solve the given equation

Answer 1

can anyone help?

Answer 2

Im here looking for answer for same problem :)

Answer 3

divide by cot(theta)

Answer 4

then simplify

Answer 5

how do you divide by it?

Answer 6

\[\csc^2/\cot=8 + 10/\cot ... \]

Answer 7

\[\csc = 1/\cot so \csc^2/\cot = \csc^3 and 10/\cot = 10\csc\]

Answer 8

i am confused? is that the answer to the equation? because it has to be somthing along the lines like 2pi/3 +2(pi)k

Answer 9

no thats just how to do it. your gonna have to finish it.

Answer 10

i dont know where to go from there?

Answer 11

?

Answer 12

just plug stuff in its gotta be either 1/2 pi/2 ... exc

Answer 13

to me, I convert \[csc^2\theta = 1+cot ^2\theta\]
therefore, yours is \[ 1+cot^2 \theta = 8cot \theta +10\\cot^2\theta-8cot\theta-9=0\\let ~\huge cot \theta =t \]
\[t^2-8t -9 =0\]
solve for t, then plug back to cot (theta) to find out the value of theta