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the average value of f(x) = e^(-2x) within the range [0, 3] ?
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\[\frac{1}{3}\int _0^3e^{-2x}dx\] is what you are looking for
dont think so
im looking for the average rate of change
anti derivative of \(e^{-2x}\) is straightforward
oh sorry, i thought it was "average value"
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the value of the secant line between those 2 points
I think it would simply be: [e^(-6) - e^0]/(3-0) ?
^ if what you want is the average rate of change in that interval.
Or [e^(-6) - 1]/3 or [(1/e^6) - 1]/3 or (1 - e^6)/3e^6 would be equivalent expressions.
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