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Mathematics 7 Online
OpenStudy (anonymous):

the average value of f(x) = e^(-2x) within the range [0, 3] ?

OpenStudy (anonymous):

\[\frac{1}{3}\int _0^3e^{-2x}dx\] is what you are looking for

OpenStudy (anonymous):

dont think so

OpenStudy (anonymous):

im looking for the average rate of change

OpenStudy (anonymous):

anti derivative of \(e^{-2x}\) is straightforward

OpenStudy (anonymous):

oh sorry, i thought it was "average value"

OpenStudy (anonymous):

the value of the secant line between those 2 points

OpenStudy (anteater):

I think it would simply be: [e^(-6) - e^0]/(3-0) ?

OpenStudy (anteater):

^ if what you want is the average rate of change in that interval.

OpenStudy (anteater):

Or [e^(-6) - 1]/3 or [(1/e^6) - 1]/3 or (1 - e^6)/3e^6 would be equivalent expressions.

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