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OpenStudy (anonymous):
@whpalmer4?
OpenStudy (whpalmer4):
\[2x^2-4x-48\]
So what do you think we should do first? Do you see any common factors in all of those terms?
OpenStudy (anonymous):
divide all of the terms by 2
OpenStudy (whpalmer4):
Okay, that's a good start.
\[2(x^2-2x-24)\]Right?
OpenStudy (anonymous):
yesh
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OpenStudy (anonymous):
is it 2(x − 6)(x + 4)?
OpenStudy (whpalmer4):
yesh? have you been imbibing? :-)
OpenStudy (anonymous):
no I just couldint figure the first part out! Thanks!
OpenStudy (whpalmer4):
well, let's see!
\[(x-6)(x+4) = x(x+4) - 6(x+4) = x^2 + 4x -6x -24 = x^2 -2x -24\]
so if we multiply that by 2, we get our starting equation, good job!
OpenStudy (anonymous):
great!
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OpenStudy (anonymous):
@Loujoelou did you need something?
OpenStudy (whpalmer4):
just watching the exciting sport of competitive factoring :-)
OpenStudy (whpalmer4):
coming soon to a television channel near you!
OpenStudy (whpalmer4):
at about 4:30 AM, I think :-)
OpenStudy (anonymous):
XD :P it is very competitive!
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