Write the equation of a line in slope intercept form that passes through (2,4) and (5,4).
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OpenStudy (jdoe0001):
so, what would be the slope of it?
OpenStudy (anonymous):
how would i find it?
OpenStudy (anonymous):
y2-y1/x2-x1
OpenStudy (jdoe0001):
well
\(\large m=\frac{y_2-y_1}{x_2-x_1}\)
OpenStudy (anonymous):
plug in and get the slope
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OpenStudy (anonymous):
then the slope would be 0/3???
OpenStudy (anonymous):
i guess yea,
OpenStudy (jdoe0001):
yes
OpenStudy (jdoe0001):
0/3 = 0
OpenStudy (jdoe0001):
so the slope is 0
now grab that and plug it in the point-slope form, with either value, say we'll pick (2,4)
plug them in, m = slope
\(\large y-y_1=m(x-x_1)\)
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OpenStudy (jdoe0001):
$$
y-y_1=m(x-x_1)\\
\text{slope of "0" and }(\color{blue}{2}, \color{blue}{4})\\
y-\color{blue}{4}=0(x-\color{blue}{2})
$$
OpenStudy (jdoe0001):
so, what would that give you?
OpenStudy (jdoe0001):
if you solve for "y"
OpenStudy (anonymous):
4....?
OpenStudy (jdoe0001):
y-4 = 0
y = 4
yes, is a flat horizontal line
let's grab the 2 points given and graph it
|dw:1372716148158:dw|
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OpenStudy (anonymous):
???
OpenStudy (jdoe0001):
the equation of the line is y = 4
OpenStudy (jdoe0001):
and is in "slope intercep" form
or
y = mx+b form
y = 4
y = 0x + 4