Question

Write an equation of a line in slope intercept form that is parallel to 6= -4x- 2passes through (-16,-11).

Answer 1

So first we should find the slope. Do you know what that is, if the equation is parallel?

Answer 2

actually it is suppose to be perpendicular (sorry little typo)

Answer 3

If slope- intercept form is y=mx+b and m=the slope. What is it?

Perpendicular if fine!

Answer 4

the slope will be
[1/4\]

Answer 5

is that 6= -4x- 2y?

Answer 6

the "y" is conspicuous for its absence

Answer 7

You're right my bad!

Answer 8

so chrissychris, what's the equation?

Answer 9

What is the starting equation?

Answer 10

no sorry let me re write the equation
y=-4x-2

Answer 11

That's fine so if we're trying to find the perpendicular equation for the point (-16, -11) the slope is still 1/4.

So we insert 1/4 into the equation y=1/4x+b

Next we must find b by inserting x & y which is (-16, -11)

Answer 12

-11

Answer 13

-11=1/4(-16) + b
-11=-4 +b
Add 4 to both sides
-8=b

Answer 14

1/4x-8 right?

Answer 15

Sorry -11+4= -7 so it would be y=1/4-7

Answer 16

My bad. Check it so -11=1/4(-16)-7
Yes. It works.

Answer 17

oh thank you so much

Answer 18

No problem, any time! I hope you understood!