Question

√(x+1)+5=x

Answer 1

I got x=6 and x=4 is this correct??

Answer 2

The first thing I would do is subtract 5 from both sides to get:
\[\sqrt{x+1}=x-5\] now square both sides:
\[x+1=(x-5)^2=x^2 -10x +25\] Simplify and we get:
\[x^2 -11x+24=0\] From here we'll need to factor. We're looking for two numbers that multiply to 24 but add to -11. These would be -8 and -3, so:
\[(x-8)(x-3)=0\] Setting each factor equal to 0, we get x=8 or x=4.

Answer 3

why did the -10x change to a -11x?

Answer 4

We subtracted an x and a 1 from both sides, to get 0 on one side.

Answer 5

Oh okay thank you so much this helped me a lot :)

Answer 6

You're welcome, glad I could help.