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OpenStudy (anonymous):
does it look like this? \[\huge \sqrt{2a - 1} = 5\]
OpenStudy (anonymous):
yes :)
OpenStudy (anonymous):
square both sides first
OpenStudy (anonymous):
to get rid of the square root on the left side
OpenStudy (anonymous):
isn't it jst 2 and 5? im not good at sqrt...
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OpenStudy (anonymous):
what do you mean just 2 and 5
OpenStudy (anonymous):
I have no clue on how to do this
OpenStudy (anonymous):
let me show you an example. maybe you'll get an idea from there
\[\huge \sqrt{5x +4} = 2\]
\[\huge \implies (\sqrt{5x + 4})^2 = (2)^2\]
\[\huge \implies 5x + 4 = 4\]
\[\huge \implies 5x = 4 - 4\]
\[\huge \implies 5x = 0\]
\[\huge \implies x = 0\]
does that give you any ideas?
OpenStudy (anonymous):
how did you move the 5 over?
OpenStudy (anonymous):
it says that its the wrong answer
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OpenStudy (anonymous):
move the 5 over? i just divided 5x = 0 both sides by 5... 0 divided by 5 is still 0 so x = 0
and that is just an example not the answer to your question...just so we're clear
OpenStudy (anonymous):
oh haha
OpenStudy (anonymous):
got it ....
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
^_^ better understand/clear the concept /....
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