Question

What is the equation of the line, in slope-intercept form, that passes through the point (4, -1) and is perpendicular to the line whose equation is 2x - y - 7 = 0?

Answer 1

@ChemGrey @amistre64

Answer 2

line given is 2x - y - 7 = 0.
in y = mx + c form => y = 2x - 7
so m1 = 2

for a line perpendicular to this, m = -1/m1
so m = -1/2
in slope intercept form.. (y - y1) = m(x - x1)
x1 = 4, y1 = -1
so equation is => (y +1) = -1(x - 4) /2
so, 2y + 2 = -x + 4
so, x + 2y - 2 = 0..
this the required equation.

Answer 3

Okay thanks :D

Answer 4

np..

Answer 5

@jumboabrfan xD seeeeeeeeeeeeeeeeeeeeeeeeeeee :D

Answer 6

2x-4y=18
3x-y+10=0
what is the first step

Answer 7

do any one know

Answer 8

@ijustdontcare make y the subject of both formulae.. then equate to get x. when u get x, simply put thevalue in any one of the two equations to get y.

Answer 9

@dan815 ?????????

Answer 10

don't get it

Answer 11

2x - 4y = 18 -> y = ( x - 9) / 2 [check on paper]
3x - y + 10 = 0 -> y = 3x + 10
so (x - 9) / 2 = 3x + 10
solve for x.
then put value of x in -> y = 3x + 10
to get y.

Answer 12

@xoya wat are you stuck on

Answer 13

Nothing