What is the value of the x variable in the solution to the following system of equations? 2x + 3y = 4 x - 2y = -5 2 -2 1 -1
do you know how to do substitution???
i spelled that wrong:D
no all I know is ellimination
oh thats fine i know that way too:)
you think you could help me(:
yup!
ummmm i think what you have to do is plug like each one in for y and solve for x...i think :D
@jdoe0001
he can help hopefully:)
okay thank you :)
np :D
@jaderbrown?
$$ 2x + 3y = 4\\ x - 2\color{red}{y} = -5 \\ \text{solve the 2nd for "y"}\\ y=\color{red}{\frac{x+5}{2}}\\ \text{now that we know what "y" equals to}\\ \text{let us use that and substitute in the 1st one}\\ 2x + 3y = 4\\ x - 2\pmatrix{\color{red}{\frac{x+5}{2}}} = -5 \\ \text{now just solve the 2nd one for "x"} $$
Cool xD
wait, I substitute it to the wrong one :/
Hahaha :D
thanks!!!
$$ 2x + 3y = 4\\ x - 2\color{red}{y} = -5 \\ \text{solve the 2nd for "y"}\\ y=\color{red}{\frac{x+5}{2}}\\ \text{now that we know what "y" equals to}\\ \text{let us use that and substitute in the 1st one}\\ 2x + 3\pmatrix{\color{red}{\frac{x+5}{2}}} = 4\\ x - 2y = -5\\ \text{now just solve the 2nd one for "x"} $$
there
eliminate y for either equation
sorry I went to the store, so I got x=2y-5
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