What is the value of the x variable in the solution to the following system of equations?
2x + 3y = 4
x - 2y = -5
2
-2
1
-1
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OpenStudy (foreverandalways13):
do you know how to do substitution???
OpenStudy (foreverandalways13):
i spelled that wrong:D
OpenStudy (anonymous):
no all I know is ellimination
OpenStudy (foreverandalways13):
oh thats fine i know that way too:)
OpenStudy (anonymous):
you think you could help me(:
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OpenStudy (foreverandalways13):
yup!
OpenStudy (foreverandalways13):
ummmm i think what you have to do is plug like each one in for y and solve for x...i think
:D
OpenStudy (foreverandalways13):
@jdoe0001
OpenStudy (foreverandalways13):
he can help hopefully:)
OpenStudy (anonymous):
okay thank you :)
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OpenStudy (foreverandalways13):
np :D
OpenStudy (anonymous):
@jaderbrown?
OpenStudy (jdoe0001):
$$
2x + 3y = 4\\
x - 2\color{red}{y} = -5 \\
\text{solve the 2nd for "y"}\\
y=\color{red}{\frac{x+5}{2}}\\
\text{now that we know what "y" equals to}\\
\text{let us use that and substitute in the 1st one}\\
2x + 3y = 4\\
x - 2\pmatrix{\color{red}{\frac{x+5}{2}}} = -5 \\
\text{now just solve the 2nd one for "x"}
$$
OpenStudy (anonymous):
Cool xD
OpenStudy (jdoe0001):
wait, I substitute it to the wrong one :/
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OpenStudy (anonymous):
Hahaha :D
OpenStudy (foreverandalways13):
thanks!!!
OpenStudy (jdoe0001):
$$
2x + 3y = 4\\
x - 2\color{red}{y} = -5 \\
\text{solve the 2nd for "y"}\\
y=\color{red}{\frac{x+5}{2}}\\
\text{now that we know what "y" equals to}\\
\text{let us use that and substitute in the 1st one}\\
2x + 3\pmatrix{\color{red}{\frac{x+5}{2}}} = 4\\
x - 2y = -5\\
\text{now just solve the 2nd one for "x"}
$$
OpenStudy (jdoe0001):
there
OpenStudy (anonymous):
eliminate y for either equation
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