Question

How can -4x^2-6x+4 be factored?

Answer 1

what method u need to use?

Answer 2

I'm supposed to solve it.
\[\sqrt{4-6x}=2x\] is the original

Answer 3

I know you square both sides like so

\[(\sqrt{4-6x})^2=(2x)^2\]

Which get you \[4-6x=4x^2\] I think.

Answer 4

divide by 2

\[2x^2+3x -2=0\]

Answer 5

divide again by 2

\[x^2 +\frac{ 3 }{ 2 }x-1=0\]

Answer 6

(x )(x ) two numbers

the sum would be 3/2
the multiplication would be 1

Answer 7

did you get it?

Answer 8

\[(x+2)(x-\frac{ 1 }{ 2 })=0\]

Answer 9

Thank You. That cleared it up alot.