Question

help please

Answer 1

Multiply the denominator by the conjugate:\[\bf \frac{ 6 }{ 4+\sqrt2 }=\frac{ 6(4-\sqrt2 )}{( 4+\sqrt{2})(4-\sqrt{2}) }=\frac{ 6(4-\sqrt2 )}{14}=\frac{ 3(4-\sqrt2 )}{7}=?\]Can you finish the last step in the simplification?

@jazzyfa30

Answer 2

\[\frac{ 12-\sqrt{2} }{ 7 }\]

Answer 3

@genius12

Answer 4

You're missing something. You didn't do the multiplication correctly in the numerator. Look again. @jazzyfa30

Answer 5

ummmm\[\frac{ -10 }{ 7 }\]

Answer 6

@genius12