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Mathematics 20 Online
OpenStudy (anonymous):

The graphs y = 2x and y =(1/2)x are _____ of each other across the y-axis.

OpenStudy (anonymous):

a.reflections c.equals b.twins d.duplicates

jimthompson5910 (jim_thompson5910):

are these exponential functions?

OpenStudy (dan815):

|dw:1372831925097:dw|

OpenStudy (dan815):

do you mean -1/2 x by any chance

OpenStudy (anonymous):

i copied and pasted my question and those are the possible answers up there^^^^^

jimthompson5910 (jim_thompson5910):

I don't think everything pasted correctly

OpenStudy (anonymous):

ill check again

OpenStudy (dan815):

none of the above

OpenStudy (dan815):

feternal twins of each other

OpenStudy (anonymous):

its all pasted right

OpenStudy (zzr0ck3r):

1/2x is the inverse of 2x so they are symmetric across y=x but not the x axis

jimthompson5910 (jim_thompson5910):

are you sure the equations aren't \[\large y = 2^x\] and \[\large y = \left(\frac{1}{2}\right)^x\]

OpenStudy (dan815):

pick A reflections i think the question wanted to ask across y = x

OpenStudy (anonymous):

thats what it is haha

OpenStudy (anonymous):

my bad

OpenStudy (dan815):

wOOOWwwww

OpenStudy (zzr0ck3r):

im good:)

OpenStudy (anonymous):

haha

OpenStudy (dan815):

WOOOWWWWWwWWWww how many times did u double check

OpenStudy (dan815):

|dw:1372832411747:dw|

OpenStudy (anonymous):

well it looks it isnt suppose to be a power but i guess it is that would make more sense

OpenStudy (anonymous):

so what is it?

OpenStudy (dan815):

oh i see ok

jimthompson5910 (jim_thompson5910):

graph the two equations and you'll see it

OpenStudy (dan815):

|dw:1372832505429:dw|

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