Mathematics
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OpenStudy (anonymous):
The graphs y = 2x and y =(1/2)x
are _____ of each other across the y-axis.
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OpenStudy (anonymous):
a.reflections c.equals
b.twins d.duplicates
jimthompson5910 (jim_thompson5910):
are these exponential functions?
OpenStudy (dan815):
|dw:1372831925097:dw|
OpenStudy (dan815):
do you mean -1/2 x by any chance
OpenStudy (anonymous):
i copied and pasted my question and those are the possible answers up there^^^^^
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jimthompson5910 (jim_thompson5910):
I don't think everything pasted correctly
OpenStudy (anonymous):
ill check again
OpenStudy (dan815):
none of the above
OpenStudy (dan815):
feternal twins of each other
OpenStudy (anonymous):
its all pasted right
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OpenStudy (zzr0ck3r):
1/2x is the inverse of 2x so they are symmetric across y=x but not the x axis
jimthompson5910 (jim_thompson5910):
are you sure the equations aren't
\[\large y = 2^x\]
and
\[\large y = \left(\frac{1}{2}\right)^x\]
OpenStudy (dan815):
pick A reflections i think the question wanted to ask across y = x
OpenStudy (anonymous):
thats what it is haha
OpenStudy (anonymous):
my bad
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OpenStudy (dan815):
wOOOWwwww
OpenStudy (zzr0ck3r):
im good:)
OpenStudy (anonymous):
haha
OpenStudy (dan815):
WOOOWWWWWwWWWww how many times did u double check
OpenStudy (dan815):
|dw:1372832411747:dw|
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OpenStudy (anonymous):
well it looks it isnt suppose to be a power but i guess it is that would make more sense
OpenStudy (anonymous):
so what is it?
OpenStudy (dan815):
oh i see ok
jimthompson5910 (jim_thompson5910):
graph the two equations and you'll see it
OpenStudy (dan815):
|dw:1372832505429:dw|