Question

What is the equation of the line, in general form, that passes through the point (-1, -1) and is parallel to the line whose equation is x + y = 3?
x-y+ 2 = 0
x+y+ 2 = 0
x+y- 2 = 0

Answer 1

line given is x + y = 3
in y = mx + c form => y = -x+3
So m1 = -1

for a line perpendicular to this, m = -1/m1

so m = -1/-1
in slope intercept form.. (y - y1) = m(x - x1)
x1 = -1, y1 = -1
so equation is => (y -1) = 1(x +1) /1
So y-1=x+1
x-y=1+1
x-y=2
So this is the required equation :)

Answer 2

So would it be x-y +2

Answer 3

xoya, the question is asking for a parallel line (not a perpendicular one)

Answer 4

Thank you.

Answer 5

Do you know what it is

Answer 6

Your welcome :D

Answer 7

Anything parallel to x+y = 3 is x+y = C where C is some fixed number

x+y = C

-1 + (-1) = C .... plug in (-1,-1)

-2 = C

C = -2

So the equation is x+y = -2

Answer 8

Cool xD

Answer 9

So it will be x + y + 2 then ok