Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).
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OpenStudy (anonymous):
please answer :(
OpenStudy (anonymous):
What is the slope of the perpendicular line to y = 2x + 2?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
The slope will have a negative reciprocal of the slope of y = 2x + 2
OpenStudy (anonymous):
the slope will be -1/2
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OpenStudy (anonymous):
So you know that the equation will be y = -1/2x and the slope is -1/2
Now it has to pass through the point (6,3)
Use the formula
\(Y - Y_1 = -\frac{1}{2}(X - X_1) \)
\(Y - 3 = -\frac{1}{2}(X - 6) \) <----can you solve
OpenStudy (anonymous):
yes okay so i add three on both sides
OpenStudy (anonymous):
no wait dont i distribute first?
OpenStudy (anonymous):
it would then be y-3=-1/2x -12 ??
OpenStudy (anonymous):
One sec I will write it out for you
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OpenStudy (anonymous):
ohk
OpenStudy (anonymous):
|dw:1372898270602:dw|
First you multiply each side by 2 to get ride of the fraction. the continue working the problem.