the graph of this equation will be which conic section? x^2+y^2=13 parabola circle hyperbola ellipse
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a circle
you can solve for y and plug it into wolfram alpha if you want. or plug in the equation and it'll assume for f(x)
or conceptually you can look at the equation x^2 + y^2 and think about on a cartesian coordinate system you when one variable approaches zero is counts for much less while the other is approaching its maximum. also since it is an exponent that has a positive number in the exponent, you may lose a negative value when it is squared (2^2 = 4 = -2^2) so there will be two values for each variable. making it not a function but a pretty good circle.
the constant it is equal to determines the size of the function but since it does not effect the variables directly the system is centered at the origin.
hurrah for wolframalpha
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