The strength of a beam is proportional to the width and the square of its depth. a beam is cut with a diameter of 30cm. Express the strenght of the beam as a function of angle theta. Use k as your constant.
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OpenStudy (anonymous):
u do spesh?
OpenStudy (jhannybean):
@Callisto
OpenStudy (jhannybean):
square of its depth....that means this beam can take on a rectangular shape?
OpenStudy (anonymous):
Yes it is rectangular beam, it is a trig question
OpenStudy (jhannybean):
I was thinking ovular, but that means the radius would constantly be increasing.....hm,just a hunch.
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OpenStudy (jhannybean):
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OpenStudy (anonymous):
|dw:1373004177030:dw|
OpenStudy (jhannybean):
oh diagonals.
OpenStudy (anonymous):
So the answer key is prompting for S(theta)=
OpenStudy (jhannybean):
what does it mean by strength....
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OpenStudy (anonymous):
It says that the strength of this beam is directly proportional to the width and depth squared