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help please... ill give a medal (:
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What's question?
\[2^\frac{ 1 }{ 3}\times4^\frac{ 1 }{ 3 }\]
simplify using the radical form
the fractions are exponents by the way
\(\large 2^\frac{1}{3} \times 4^\frac{1}{3}\)
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Try this: \[2^{\frac{ 1 }{ 3 }}\times(2^{2})^{\frac{ 1 }{ 3 }}\] Once you have the same base use the rules of exponents.
\(\large 2^\frac{1}{3} \times 4^\frac{1}{3}\) \(\large (2 \times 4)^{\frac{1}{3}} \) \(\large (2 \times 2^2)^\frac{1}{3}\) \(\large (2^3)^\frac{1}{3}\)
thanks!
yw :)
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