Use the given root to find the solution set of the polynomial x^4-4x^3+2x^2-4x+1=0; i
a) (i, -i, 2+√3, 2-√3)
b) (i, -i, -2+√3, -2-√3)
c) (i, -i, 2+2√3, 2-2√3)
d) (i, -i, 1+√3, 1-√3)

Question

Use the given root to find the solution set of the polynomial x^4-4x^3+2x^2-4x+1=0; i
a) (i, -i, 2+√3, 2-√3)
b) (i, -i, -2+√3, -2-√3)
c) (i, -i, 2+2√3, 2-2√3)
d) (i, -i, 1+√3, 1-√3)

rsadhvika · Answer

if i is a root, then -i is also a root

rsadhvika · Answer

(x-i)(x+i) is a factor of given polynomial

rsadhvika · Answer

divide the given polynomial with that factor
you would get a quadratic
apply quadratic formula

anonymous · Answer

so is the answer a?

rsadhvika · Answer

wat do you get when u divide

rsadhvika · Answer

The answer is certainly between A and C

anonymous · Answer

well after factoring i got x^2-4x+1

rsadhvika · Answer

great ! answer is A. good job !!!

anonymous · Answer

thanks for the help!!

rsadhvika · Answer

there is a trick to figure out the correct roots when you have options to pick from

rsadhvika · Answer

do u knw SUM of roots, PRODUCT of roots stuff ?

anonymous · Answer

not that well

rsadhvika · Answer

its okay then, dividing and finding the roots is straightforward way :)

anonymous · Answer

oh okay

rsadhvika · Answer

:D