Question

2x/x^2-16 plus x/x-4
*equation below

Answer 1

\[\frac{ 2x }{ x^2-16 }+\frac{ x }{ x-4 }\]

Answer 2

do u want to simplify it?

Answer 3

Firstly, factorise the bottom of the first fraction using the difference of two squares :)

Answer 4

Then put both fractions under the same denominator (x+4)(x-4).

Answer 5

so r u saying to first factor the first denominator?

Answer 6

yes :) First do that

Answer 7

ok so would it be\[\frac{ x^2+6x }{ (x-4) (x+4) }\]

Answer 8

Yes, now multiply both the numerator and denominator of the second fraction such that both fractions have the same denominator :)