Question

A person on horseback moves according to the velocity-versus-time graph shown in the figure (attached)

A. Find the displacement of the person for segment A of the motion.

B. Find the displacement of the person for segment B of the motion.

C. Find the displacement of the person for segment C of the motion.

Answer 1

the area between the graph and time axis is the displacement

Answer 2

can u put that into an equation?

Answer 3

or at least give me an example of how to solve it because I don't understand what you said

Answer 4

okay...for segment A the displacement=1/2*10*2 meter..

Answer 5

that doesn't make sense I thought you said

Answer 6

the area i painted orange..

Answer 7

I don't understand

Answer 8

displacement =velocity*time
now for segment A
displacement = the area of triangle between the graph and time axis...

Answer 9

well the area of that triangle is:

A= (1/2) base x Height which is (1/2)(10)(2) = 10

Answer 10

yeah! right!

Answer 11

now what?

Answer 12

now find it for segment B

Answer 13

that's my answer?

Answer 14

thats you answer for segment A

Answer 15

okay, but i tried it again for B, and I got it wrong

Answer 16

its 20 m for b

Answer 17

the area of trapezium under B

Answer 18

then C is 40?

Answer 19

no it is 60

Answer 20

u need to calculate the complete area between the line segment c and x axis

Answer 21

i thought i did

Answer 22

the area of trapezium under C
=1/2*(6+2)*10=40

Answer 23

yaa its 40... my mistake

Answer 24

good job !@Summersnow8

Answer 25

thanks @souvik

Answer 26

you are welcome...