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Mathematics 12 Online
OpenStudy (anonymous):

Can someone teach me how to solve this Refer to this table of results of the Indianapolis 500 in which drivers competed in the 500-mile race. To the nearest mile per hour, how much faster was the average winning speed in 2004 than in 1911? (Enter only the number.) Picture included

OpenStudy (anonymous):

OpenStudy (texaschic101):

speed = distance over time speed in 2004 : I am changing time to seconds ...3 hr and 15 s = 3600(3) + 15 = 10800 + 15 = 10815 s = 500/10815 .....s = .0462/sec thats per second, per hour would be .0462 x 3600 = 166.32/hour speed in 1911 : changing time to seconds. 6 hours 42 min = 3600(6) + 42(60) = 21600 + 2520 = 24120 s s = 500/24120 = .0207/sec per hour, that would be .0207 x 3600 = 74.52/hr 2004 speed = 166.32 1911 speed = 74.52 -------------------subtract 2004 is 91.8 miles faster

OpenStudy (anonymous):

Thank you so much

OpenStudy (texaschic101):

you might want to get a second opinion

OpenStudy (accessdenied):

I can agree with @texaschic101 's work. :) The speeds found might be a bit different depending on rounding, although the final answer was still what I got. :)

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