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Mathematics 14 Online
OpenStudy (anonymous):

Can anybody help me with this?

OpenStudy (anonymous):

OpenStudy (anonymous):

Do I use the foil method... or?

OpenStudy (anonymous):

you should know that (a+b)(a-b)=a^2-b^2. now try to solve the question.

OpenStudy (anonymous):

for (t^2-n^2) do I simplify it to (t-n)(t+n) ?

Directrix (directrix):

Multiply (t^2 - n^2) times (t^2 - n^2) and match the simplified product with one of the answer options. @RH

OpenStudy (rane):

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OpenStudy (anonymous):

@RANE its not (t-n) on the second one, its (t+n)

Directrix (directrix):

@RANE t^4 - n^4 is NOT correct. Try again. You lost the middle term. (t^2 - n^2) times (t^2 - n^2) = ?

OpenStudy (rane):

there r no bracket once u simplify the ist 2 bracket directrix

OpenStudy (rane):

ops my bad RH

OpenStudy (rane):

NO W8!

OpenStudy (anonymous):

I keep getting wrong answers!!!:( can someone explain?!

OpenStudy (rane):

@RH it becomes -ve in the 2nd equation becoz when u times -ve and +ve = -ve

OpenStudy (rane):

so there is no +ve left

Directrix (directrix):

@RH The original problem is (t-n)(t+n)(t^2-n^2). As some body above posted, the product of the first two is (t^2 - n^2). So, (t-n)(t+n)(t^2-n^2) = (t^2 - n^2) (t^2 - n^2) So, @RH, crank out (t^2 - n^2) (t^2 - n^2) and that's the answer.

OpenStudy (rane):

hun?

Directrix (directrix):

@RANE What is a "+ve "

OpenStudy (anonymous):

I got t^4 - t^2 n^2 - n^2 t^2 - n^4

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

Is A correct?

OpenStudy (rane):

yes then u simplify it @RH

OpenStudy (rane):

w8 its B

Directrix (directrix):

@RH Good. Now, collect like terms. t^4 - t^2 n^2 - n^2 t^2 - n^4 t^4 - 2 n^2 t^2 - n^4

OpenStudy (rane):

how did u get 2 @Directrix

OpenStudy (rane):

and this answer is not in the choices

OpenStudy (rane):

there is no 2

Directrix (directrix):

I see the answer in the choices. @RH Do you?

OpenStudy (anonymous):

It is A right?

OpenStudy (rane):

which option?

OpenStudy (anonymous):

t^2-n^2=(t+n)(t-n) substitute and multiply

OpenStudy (rane):

where did u get 2 @RH

Directrix (directrix):

@RH > It is A right? YES, it is, @RH.

OpenStudy (anonymous):

ans is c

OpenStudy (rane):

thats wht i said

OpenStudy (rane):

no rina it cant be

OpenStudy (anonymous):

got it @RH

OpenStudy (anonymous):

I am so confused right now!!!!!

Directrix (directrix):

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