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簡化x^2-8xy+16y^2
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Factorization
so it is\[x ^{2}-8xy+16y ^{2}\]
it is of the form a^2-2ab+b^2=(a-b)^2
ok carry on @uri
ok @uri
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Lol im busy learning something.
\[x ^{2}-4xy-4xy+16y ^{2}\]
did u get it @kakikkkk
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why do i feel "簡化" is a key statement here...
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is Factorization
only have Answer?
\[x^{2}-8xy+16y^{2}=x^{2}-2.x.4y+(4y)^{2}\]
@kakikkkk NOW change the above expression in the form \[(a-b)^{2}\]
@kakikkkk x^2 - 8xy + 16 y^2 = (Look for two numbers that multiply to 16 and add to -8) x^2 - 4 xy - 4 xy + 16 y^2 = (factor by grouping) x (x - 4y) -4y (x - 4y) = [ (x - 4y) is the common factor ] (x - 4 y) * ( ? - ?)
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