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Mathematics 16 Online
OpenStudy (anonymous):

簡化x^2-8xy+16y^2

OpenStudy (anonymous):

Factorization

OpenStudy (shamim):

so it is\[x ^{2}-8xy+16y ^{2}\]

OpenStudy (anonymous):

it is of the form a^2-2ab+b^2=(a-b)^2

OpenStudy (anonymous):

ok carry on @uri

OpenStudy (shamim):

ok @uri

OpenStudy (uri):

Lol im busy learning something.

OpenStudy (shamim):

\[x ^{2}-4xy-4xy+16y ^{2}\]

OpenStudy (shamim):

did u get it @kakikkkk

OpenStudy (anonymous):

only have Answer?

OpenStudy (anonymous):

why do i feel "簡化" is a key statement here...

OpenStudy (anonymous):

is Factorization

OpenStudy (anonymous):

only have Answer?

OpenStudy (anonymous):

\[x^{2}-8xy+16y^{2}=x^{2}-2.x.4y+(4y)^{2}\]

OpenStudy (anonymous):

@kakikkkk NOW change the above expression in the form \[(a-b)^{2}\]

Directrix (directrix):

@kakikkkk x^2 - 8xy + 16 y^2 = (Look for two numbers that multiply to 16 and add to -8) x^2 - 4 xy - 4 xy + 16 y^2 = (factor by grouping) x (x - 4y) -4y (x - 4y) = [ (x - 4y) is the common factor ] (x - 4 y) * ( ? - ?)

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