Question

Find the angle between the given vectors to the nearest tenth of a degree.

u = <6, -1>, v = <7, -4>

Answer 1

Please someone reply

Answer 2

I have no I idea what that means

Answer 3

Use dot product of the vectors...in this case

u.v=lul lvl cos(theta)... Find magnitudes of u and v and on LHS use rule of dot product..i;e multiply x componets togather and y components togather and add them scalarly.. Solve for cos (theta) and take arc cos to get answer

Answer 4

got it?

Answer 5

I thinks so

Answer 6

So it would be 6*7 + -1*-4 / sqrt6+7 sqrt-1+-4

Answer 7

cos(theta)=(6*7+-1*-4)/[sqrt(6^2+1^2) sqrt(7^2+4^2)]...

Answer 8

I got 20.3 as the answer

Answer 9

Is that right

Answer 10

Yes...My medal?