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Mathematics 21 Online
OpenStudy (anonymous):

4y^2+48y+144

OpenStudy (anonymous):

what do you need to do?

OpenStudy (uri):

Quadratic equation?

OpenStudy (uri):

Factorize?

OpenStudy (anonymous):

nevermind looks like uri wants this one lol

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

uri is so fast

OpenStudy (anonymous):

factor

OpenStudy (uri):

@kellyking If it's a Quad eq the apply this formula : http://blogs.discovermagazine.com/loom/files/2008/07/quadratic.jpg

OpenStudy (uri):

Oh factor wait.

OpenStudy (uri):

4y^2+48y+144 4(y^2+12y+36) Formula: (a+b)^2= a^2+2ab+b^2 4(y+6)^2

OpenStudy (anonymous):

that's the answer I kept getting but in the book it says (2y + 12)

OpenStudy (uri):

(y+6)^= y^2+2(y)(6)+(6)^3 Understood?

OpenStudy (uri):

It will be (2y+12)^2 not (2y+12)

OpenStudy (uri):

This is beacuse they didn't take common See applying the formula here will solve 4y^2+48y+144 (2y)^2+2(2y)(12)+(12)^2 (2y+12)^2 So, did you understand now? :)

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