Question

An acute angle θ is in a right triangle with sin θ = 7/8. What is the value of cot θ?

Answer 1

theta will be sin inverse of 7/8.... then after that idk..cos we dont do cot

Answer 2

find the third side via pythagoras
it is
\[\sqrt{8^2-7^2}=\sqrt{64-49}=\sqrt{15}\]

Answer 3

then cotangent is "adjacent over opposite"

Answer 4

oh so cot is like the opposite of tan

Answer 5

so its 15/8

Answer 6

no, it is \(\frac{\sqrt{15}}{7}\)

Answer 7

the "adjacent " side is \(\sqrt{15}\)and the "opposite" side is \(7\)