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OpenStudy (jhannybean):
It's the same method for this one...instead of |x| we have | x+2 | so you know the out come is going to be 2 values.
First isolate |x+2| to one side.
|x+2| = 14-16
|x+2| = -2
Opening up the absolute value you'll have
x+2 = -2 or x+2 = 2
Evaluate x for both of these functions.
OpenStudy (jenniferjuice):
x = −32 and x = −4
x = −4 and x = 0
x = 0 and x = 28
No solution
OpenStudy (jenniferjuice):
i got zero and zero
OpenStudy (jenniferjuice):
?
OpenStudy (jenniferjuice):
@Jhannybean
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OpenStudy (jenniferjuice):
okay thankyou
OpenStudy (jhannybean):
wait a minute, no....
OpenStudy (jenniferjuice):
wait whaaaaa
OpenStudy (jhannybean):
x+2= -2
x = -2 - 2
x+2 = 2
x = 2 - 2
OpenStudy (jenniferjuice):
now what?
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OpenStudy (jhannybean):
Solve for x, i think you made an error. It's actually not 0, 0 ..
OpenStudy (jenniferjuice):
x+2 = -2
-2 -2
x= -4
OpenStudy (jenniferjuice):
yeah i messed up there
OpenStudy (jhannybean):
good.
OpenStudy (jhannybean):
so your values are?...
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