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OpenStudy (anonymous):
if f(x)= log {(1+x)/(1-x)} then f (x) is
a) an even function
b) an odd function
c) neither even nor odd
d) a constant term
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OpenStudy (jack12):
no im sorry
OpenStudy (jack12):
the answer is C
OpenStudy (anonymous):
i don't think so !
terenzreignz (terenzreignz):
LOL
ganeshie8 (ganeshie8):
evaluate f(-x)
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terenzreignz (terenzreignz):
Someone has pretty powerful instincts :D
OpenStudy (jack12):
what do you think it is a constant term?
OpenStudy (jack12):
E its a cheese cake
terenzreignz (terenzreignz):
\[\Large f(x) = \log\left(\frac{1+x}{1-x}\right)\]
Let's evaluate f(-x)
\[\Large f(\color{red}{-x}) = \log\left(\frac{1-x}{1+x}\right)\]
OpenStudy (anonymous):
it is an odd function !
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terenzreignz (terenzreignz):
Which, incidentally... is...
\[\Large f(\color{red}{-x}) = \log\left(\frac{1+x}{1-x}\right)^{-1}\]
OpenStudy (jack12):
i didn't realize the denominator was inside the logarithm nvm
OpenStudy (jack12):
your tex wasn't formatted properly
ganeshie8 (ganeshie8):
you have powerful insticnts and you're superfast also krit ;p
OpenStudy (binary3i):
so @terenzreignz
says
f(-x)=-f(x)
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OpenStudy (anonymous):
i have got another one !
ganeshie8 (ganeshie8):
okiee
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