Question

A rectangle is 12m longer than it is wide. Its perimeter is 76m.


An equation to find the perimeter is=
Its width is=
Its length is=

Answer 1

We know that the perimeter of a rectangle is equal to twice its width plus twice its height or:
\[P=2l + 2w\] Lets let w=width of the rectangle. We know that the length is 12+w. The perimeter is 76m. Lets plug these values in:
\[76m=2(w) + 2(w+12)\] Can you solve from here?

Answer 2

4w + 12 = 76?

Answer 3

Close, you have to distribute the 2 on the right side of the equation to the 12, so you would have
\[76m = 2w + 2w +24=4w+24\]

Answer 4

??

Answer 5

so how do you get the w= and l=

Answer 6

Solve this equation for w:
\[4w+24=76m\]

Answer 7

13 is w

Answer 8

now length?

Answer 9

You're told in the equation that the length is 12m more than the width, so if the width is 13, the length has to be 12+13 or 25m.