1B-2 c)

Maybe it's because I've been at this all day, but I cannot figure out why s(b/32)= b^2/64

For those who do not wish to search for reference,
b is initial velocity in f/s.
s is distance in feet
t is time in seconds

s= bt−16t^2
v= ds/dt at t - v=b-32t as h-0

so max height is at t=b/32 (the time that v=0)
I understand that s(b/32) should give me the answer, but I must be missing something in the algebra.

Danke

Question

1B-2 c)

Maybe it's because I've been at this all day, but I cannot figure out why s(b/32)= b^2/64

For those who do not wish to search for reference, 
b is initial velocity in f/s.
s is distance in feet
t is time in seconds

s= bt−16t^2
v= ds/dt at t -> v=b-32t as h->0

so max height is at t=b/32 (the time that v=0)
I understand that s(b/32) should give me the answer, but I must be missing something in the algebra.

Danke

anonymous · Answer

s(b/32)=b*(b/32)-16*(b/32)^2
           =b^2/32-b^2/64
s(b/32)=b^2/64...
 what's the problem??

anonymous · Answer

I see it now, had to sleep on it I guess.

I finally broke everything down as powers of 2 and it was easy to see.

Thank you.