5/x= 6/x-1/3
\[\frac{ 5 }{ x }=\frac{ 6 }{ x}-\frac{ 1 }{ 3 }\]
simplify the equation first by multiplying by the reciprocals
18-x/3x
try multiplying the WHOLE equation by the reciprocal of 1/ x
can you draw it out cuz im a little confused?
|dw:1373348996693:dw|
x 5 6 1 --- [ --- = --- - --- ] 1 x x 3
thats how it would look then you can cancel out numbers, varables etc and simplify
\[\frac{ 5x }{ x}=\frac{ 6x }{ x }-\frac{ x }{ 3 }\]
yep
now what do i do after that?
cancel :O
cancel what? if itn's not times i thought you can't cancel?
\[\frac{5}{x}-\left(-\frac{1}{3}+\frac{6}{x}\right)=0\]\[\frac{x-3}{3 x}=0 \]x = 3
12345 qwert 12345 --------- ------ 19 qwert 19
it is a essentially a multiplication problem 5 x --- . --- you are multiply by the reciprocal x 1
you cancel out a term
x but that leaves you with 5 and the answer in my book is 3?
youre not done yet -.-
ok, sorry i'm confused, did you go back?
on simplification yes
anyways simplify the whole equation just to make it look easier to solve
\[\frac{5}{x} = \frac{6}{x} -\frac{1}{3}\]multiply everything by \(x\) \[5 = 6 - \frac{x}{3}\]subtract 6 from both sides \[-1=-\frac{x}{3}\]multiply both sides by -3 \[3 = x\]
Check:\[\frac{5}{3} = \frac{6}{3} - \frac{1}{3} \]\[\frac{5}{3} = \frac{6-1}{3} = \frac{5}{3}\checkmark \]
ahhhh that makes sense
that's always the goal :-)
how did you know to multiply it by x, i have alot of problems like this so i'm just wondering
you could also say that given the numerators show 5 = 6 - 1, that x must = 3 so the denominators are equal...
oh, when faced with fractions, multiply by the denominators to get rid of the fractions.
we could have multiplied by 3x here and done it all in one step: \[\frac{5}{x} = \frac{6}{x} - \frac{1}{3} \]multiply by \(3x\) \[3x*\frac{5}{x} = 3x*\frac{6}{x} - 3x*\frac{1}{3}\]\[15 = 18-x\]\[-3 = -x\]\[x = 3\]
ah, ok thank you very much!
good luck!
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