Find the area of a rectangular object which has a length of 2√3 and a width of 3√6. Explain, in complete sentences, how you arrived at the simplified answer and give the final solution in simplified radical form. What type of object might this be?
what is the area of a rectangular object ?
b x h
l * b (l = length b = breadth) so putting the values given in the ques. what expression do you get ?
2√3 x 3√6 ?
yes, so \[3\sqrt{6} = 3 \sqrt{2\times3} = 3 \sqrt{2}\sqrt{3}\]
so 2sqrt(3) * 3sqrt(2)*sqrt(3) = 2*3*(sqrt(3) * sqrt(3))*sqrt(2)
clear?
what do you do with the 2√3 ?
2sqrt(3) = 2* sqrt(3) so all i have done is paired this sqrt(3) with other one
are the * = multiplication ?
yes
generally +/ - = addition/subtration * = multiplication / = divide ^ = raised to power
ooh so 2√3 x 3√2 x √3 = 2 x 3 x √3 x √3 x √2 is the answer ?
no we can simplify more sqrt(3) * sqrt(3) = 3 and 2*3 = 6 so 6 * 3 * sqrt(2) 18*sqrt(2) \[18\sqrt{2}\] is the answer
okay thank you !
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