Find the area of a rectangular object which has a length of 2√3 and a width of 3√6. Explain, in complete sentences, how you arrived at the simplified answer and give the final solution in simplified radical form. What type of object might this be?
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OpenStudy (harsimran_hs4):
what is the area of a rectangular object ?
OpenStudy (anonymous):
b x h
OpenStudy (harsimran_hs4):
l * b (l = length b = breadth)
so putting the values given in the ques. what expression do you get ?
OpenStudy (anonymous):
2√3 x 3√6 ?
OpenStudy (harsimran_hs4):
yes, so
\[3\sqrt{6} = 3 \sqrt{2\times3} = 3 \sqrt{2}\sqrt{3}\]
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OpenStudy (harsimran_hs4):
so 2sqrt(3) * 3sqrt(2)*sqrt(3) = 2*3*(sqrt(3) * sqrt(3))*sqrt(2)
OpenStudy (harsimran_hs4):
clear?
OpenStudy (anonymous):
what do you do with the 2√3 ?
OpenStudy (harsimran_hs4):
2sqrt(3) = 2* sqrt(3)
so all i have done is paired this sqrt(3) with other one
OpenStudy (anonymous):
are the * = multiplication ?
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OpenStudy (harsimran_hs4):
yes
OpenStudy (harsimran_hs4):
generally
+/ - = addition/subtration
* = multiplication
/ = divide
^ = raised to power
OpenStudy (anonymous):
ooh so 2√3 x 3√2 x √3 = 2 x 3 x √3 x √3 x √2 is the answer ?
OpenStudy (harsimran_hs4):
no we can simplify more
sqrt(3) * sqrt(3) = 3
and 2*3 = 6
so 6 * 3 * sqrt(2)
18*sqrt(2)
\[18\sqrt{2}\] is the answer